Q12-2 Gravitation 1. Find the speed of a satellite in a circular orbit around the Earth...
A satellite in a circular orbit around the earth with a radius 1.015 times the mean radius of the earth is hit by an incoming meteorite. A large fragment (m = 89.0 kg) is ejected in the backwards direction so that it is stationary with respect to the earth and falls directly to the ground. Its speed just before it hits the ground is 359.0 m/s. Find the total work done by gravity on the satellite fragment. RE 6.37·103 km;...
6. [2pt] A satellite is in a circular orbit around the Earth. The period of the satellite is 26.7 hr. Calculate the radius of the satellite's orbit. Data: ME=5.98 x 1024 kg, G = 6.67 x 10-11 Nm²/kg2. Answer: Submit Al Answers 7. [2pt] What is the speed of the satellite in the previous problem? Answer: (Submit All Answers)
2. Gravitation A 1,000 kg satellite orbits Earth at a constant altitude of 100 km. How much energy must be added to the system in order to move the satellite into a circular orbit with a radius of 10,000 km? G 6.67 x 10-11 Nm2kg2, radius of Earth: 6.37 x 10 m, Mass of Earth: 5.98 x 104kg.
1. A satellite's in a circular orbit around the earth. The period of the satellite is 25.4 hr and the radius of the orbit of the satellite is 4.39 x 107m (Mass of Earth = 5.98 x 1024 kg) What's the speed of the satellite?
Find the speed of a satellite in a circular orbit around the Earth with a radius 2.77 times the mean radius of the Earth. (Radius of Earth -6.37x103 km, mass of Earth 5.98x1024 kg, G - 6.67x10 11 Nm2/kg2.)
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
6. [2pt] A satellite is in a circular orbit around the Earth. The period of the satellite is 20.9 hr. Calculate the radius of the satellite's orbit. Data: My = 5.98 x 10kg, -6.67 x 10 Nm²/kg? Answer: Not yet correct, tries 1/20 S t Al Answers Last Answer: 4.8x10^21 m Hint: Uniform circular motion means that the satellite is accelerated towards the center. The acceleration can be obtained from the law of gravity and the second law combined.
A satellite is in a circular orbit around the Earth at an altitude of 2.52 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law: T2 =(4π^2/GMs)r^3 so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.) _______________h (b) Find the speed of the satellite. _________km/s (c) Find the acceleration of the satellite....
What speed must a satellite have if it is to move in a circular orbit of 610 km above the surface of the Earth? (The Earth's radius is 6400 km and the Earth's mass is 5.98*1024 kg.)
A satellite is in a circular orbit about the Earth at a distance of four (4) Earth radii above the surface of the Earth. What is the velocity of the satellite? (Earth's mass: ME = 5.98 x 1024 kg; the radius of the Earth: 6.4 x 106m ; G = 6.67 x 10-11 Nm2/kg2 ). A) 4,072.5 m/s B)3,530.5 m/s C)5,582.2 m/s D)7,465.9 m/s