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Please correctly complete this question set to have ten percent added to your exam II score. You can increase your score to u
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Answer #1

let v is the speed of the blocks after moving 1.72 m

Apply conservation of energy

gain in kinetic energy = loss of potential energy

(1/2)*(m1 + m2)*v^2 = m2*g*d - m1*g*d*sin(33)

(1/2)*(18.4 + 12.75)*v^2 = 12.75*9.8*1.72 - 18.4*9.8*1.72*sin(33)

15.575*v^2 = 46

v = sqrt(46/15.575)

= 1.72 m/s <<<<<<<<--------------Answer

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