Question

5. A mass of 225 g is suspended from a vertical spring. It is then pulled down 15 cm and released. The mass completes 10 oscillations in a time of 32 seconds. What is the force constant for the spring? 6. A block of unknown mass is attached to a spring with a force constant of 6.50 N/m and undergoes simple harmonic motion with an amplitude of 10.0 cm. When the block is halfway between its equilibrium position and the end point, its speed is measured to be 30 cm/s. Calculate a) the mass of the block, b) the period of the motion, and c) the maximum acceleration of the block.

Answer 1

6 Time period. T220 m n = 20 m Time period T= 32 = 3:2 see - T²472 (m) K = 476?m k 4X3-14) 2x0.225 (3.22 force.com steunt for the Spring Ko 0.84 MM ♡ K = 6.5 Nm , Amplitude As locm=0.1m at x = 2 = 300m/s = 0.3 m/s usmg conservation of energy CA2 = £ kx2 + 2 mv 2 K(A²x²) = mv2 - K(A2-x2) 6.58 0.1)? (0.057] (0. 32 * m= 0.542 kg] = 2x3.14x) 045 = 1.813 80 To 2 V Fra 1.813 see/ o may acceleration amay = A 2 SAID=0.1xlmond amax = 1.2 m/s2