Question

A rotating wheel requires 8.00 s to retate 30.0 revolutions. Its angular velocity at the end of the 8.00s interval is 99.0 rad/s. What is the constant angular acceleration of the wheel? (Do not assume that the wheel starts at rest.) Note the values in this s question above. rad/s2 The final a 7.17 Need Help? Read Talk to Tuter

Answer 1

Sogho- - Speed at the end of time tzts wo wo tyt Where wo= initial angular speed to . W = speed at stime t =ggrad's x = Angular acceleeation V ggrad/s = Wota (25) We = 99 - *(B) traveled distance in time t=85 o = wott hat² Where o=30 revolution =(211) 30 =188.196 rad a 188 nabrad = wol85) + 1 x 1852 188.496 rad = (99-4(8)) (8) + 1 4 (8)2 188.496 = 792-a(64) + 329 F = 1886 rad/s2 L.