Question

A 0.750 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.900 N to displace the glider to a new equilibrium position, x= 0.050 m. O000 +X Find the effective spring constant of the system. 18 N/m Pretend the two springs are acting like one single spring and use Hooke's Law. Submission not graded. Use more digits. Previous Tries 1/12 Tries Submit Answer The glider is now released from rest at x= 0.050 m. Find the maximum x- acceleration of the glider. Submit Answer Tries 0/12 Find the x-coordinate of the glider at time t= 0.630T, where T is the period of the oscillation. Submit Answer Tries 0/12 Find the kinetic energy of the glider at x=0.00 m. Tries 0/12 Submit Answer

Answer 1

A)

Effective spring constant, k = F/x

k = 0.9/0.05 = 18 N/m

B)

Angular velocity, w = sqrt(18/0.75) = 4.90 rad/sec

Acceleration, a = - 4.9^2 x 0.05 cos(2 pi x 0.63) = 0.82 m/s^2

C)

X = 0.05 cos(2 pi x 0.63) = - 0.034 m

D)

Velocity, v = 0.05 x 4.9 = 0.245 m/s

Kinetic energy, E = 0.5 x 0.75 x 0.245^2 = 0.023 J

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