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Two solutions, one with a mass of 38.60 g, initially at 22.57 °C, and one with a mass of 50.81 g, initially at 26.82 °C were

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Answer #1

Q= mS∆T

Q= heat change

m= Mass of substance

S= heat capacity

∆T = change in temperature

o= msot = m m= mass of substance s = Specific Heat Capa City Tf = final temperature Ti = initial temperature 0 m, = 38.60gm T

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