Question

Two 2.4-cm-diameter-disks spaced 1.6 mm apart form a parallel plate capacitor. The electric field between the disks s 4.7x10⁵ V/m

How much charge is on each disk? 

An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.1x10' m/s. What was th left the negative plate? 

Answer 1

Two disks are placed at a distance are forming a parallel plate capacitor. Capacity of the capacitor can be calculated with the help of knowing area of plates and distance between the two plates. Electric field is given hence we ca calculate the potential difference between the plates. Charge stored on the capacitor is Q = C V

If we calculate the total charge stored then charge on two plates are just one plate positively charged and other negatively charged with the same charge calculated.

Other part is solved with the help of using equation of motion.

Two scanned sheets of solution are attached here.