Two 2.4 cm diameter disks spaced 1.5 mm apart form a parallel-plate capacitor
Two 2.4-cm-diameter-disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.9×105 V/m . Part A) *ANSWERED - What is the voltage across the capacitor? - V=740V Part B) How much charge is on each disk? q1,q2= ?C Part C) An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×107 m/s . What was the electron's speed as it left the negative plate? vinitial= ??
Two 2.4-cm-diameter-disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.1×105 V/m . A. What is the voltage across the capacitor? B. How much charge is on each disk? (in C) C. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.4-cm-diameter-disks spaced 1.8 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.2×105 V/m A) What is the voltage across the capacitor? C) An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.4×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.4-cm-diameter-disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is 5.0×105 V/m . A)What is the voltage across the capacitor? Express your answer with the appropriate units. (answer 1000 Volts) B)How much charge is on each disk? Express your answers in coulombs separated by a comma. C) An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.5×107 m/s .What was the electron's speed as it...
Two 2.4 cm -diameter disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.8×10^5 V/m. Part A: What is the voltage across the capacitor? V= 960 V is correct Part B: How much charge is on each disk? q1, q2= ?? C *Definitely not sure how to do this one. Part C: An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.0×10^7 m/s . What...
Two 2.1-cm-diameter-disks spaced 1.6 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.8×105 V/m . What is the voltage across the capacitor? How much charge is on each disk?An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.5×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.4-cm-diameter-disks spaced 1.6 mm apart form a parallel plate capacitor. The electric field between the disks s 4.7x105 V/mHow much charge is on each disk? An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.1x10' m/s. What was th left the negative plate?
Two 2.3-cm-diameter-disks spaced 1.9 mm apart form a parallel-plate capacitor. The electric field between the disks is 5.0×105 V/m . How much charge is on each disk? b. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.2×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.5-cm-diameter-disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.5×105 V/m . An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.5×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.0-cm-diameter-disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 5.0×105 V/m . Part C An electron is launched from the negative plate. It strikes the positive plate at a speed of2.0×107 m/s . What was the electron's speed as it left the negative plate? Express your answer with the appropriate units.