answer)
N = 100
P = 0.74
First we need to check the conditions of normality that is if n*p and n*(1-p) both are greater than 5 or not
N*p = 74
N*(1-p) = 26
Both the conditions are met so we can use standard normal z table to estimate the probability
z = (oberved p - claimed p)/standard error
Standard error = √{claimed p*(1-claimed p)/√n
Observed p = 0.76
Claimed = 0.74
N = 100
Z = 0.45
From z table, P(z>0.45) = 0.3264
8.2.16 Question Help According to a study the proportion of people who are satisfied with the...
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