(a) What is the vapor pressure of water at 20.0◦C? (b) What percentage of atmospheric pressure...
(a) What is the vapor pressure of water at 20.0◦C? (b) What percentage of atmospheric pressure does this correspond to? (c) What percent of 20.0◦C air is water vapor if it has 100% relative humidity? (The density of dry air at 20.0◦C is 1.20 kg/m3).
I got that the vapor pressure of the water will be 2.33x103 Pa, but I am getting hung up on the formula for part b, which is where I can really use the extra help and explanation. Thanks!
Homework Answers
b)
Divide the vapor pressure by atmospheric pressure:
2.33x103 / (1.01*105) *100 = 2.30%
c)
The density of water in this air is equal to the saturation vapor density of water at this temperature, taken as 1.72*10-2 kg/m^3 Dividing by the density of dry air, we can get the percentage of water in the air:
1.72*10-2 kg/m^3 /(1.20 kg/m^3) *100 = 1.43 %
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