Question

Titration of Acids and Bases 5. Sodium carbonate is a reagent that may be used to standardize acids in the same way you used KHP in this experiment. In such a standardization, it was found that a 0.512 sample of sodium carbonate required 26.30 mL of a sulfuric acid solution to reach the end point for the reaction. Na CO2(aq) + H2SO (aq) →H2O(1)+ CO2(8)+ Na 50 (aq) What is the molarity of the H,SO 2 6. A solution contains 6.30x10-2g of oxalic acid, H,C,0, 2,0, in 250 mL. What is the molarity of this solution?
Lab

Answer 1

5) Nazco(a)H30 H200 + co,)Na250a Itis the balaneed chamical eguation asoeause the toal no of each elamemts atoms. ago aame on both'zdos So, aceondiva to tue equation, Lmole of Na,ca3 wacts with Lmole of H2s04 Lmot of H20 , Imsle t e0, & Imsie ot Na,so4 i O.5122 f Na,co3 required 26.30 mL of H2S0A to eaeh the endpoint of th titration we have to find out the molarity(eoneentration) the Hs0, Solution Solution Molasr masi of Na,co2 = L06 O.512 Na2c03 -3 0.512- 4.83 x10 mol Naze03 eigt taken () Molar mas (M) : no, 6 moles (m) , -3 . 4.83 Lomol f Na,eo3 eacbed with 4.83x10mo H2S0A acecor ding to the ehemieal eqyation

Now, 4.83x mol f Hs04ere pesent in 26.30 mL Volume of the aeid salutioni 26.30 mL Volume eontainia A.83KLo mole of H2s04 4.83x103 mL 26.30 1000 A.83x1100D moles 26.30 0.184 moles of HS04 ooDmL volume Solution s eontoining 0.184 maler o 2s04. Therefore, he eoneentration of the H2504 30lution 0.184 (M) mo. moles a solute presentin Lo00 mL Volume th solution 2. Molarity 6) 6.30x162 of oxalie aeid,(H,C,04220) Peetn 250 mL volume-of the Solution. NO, Molar masa of the oxalke aeid baken(H, e204.2H20) (2 x1) +(2x12)(AR16)2[2x ) 4 1e] mol 126 moi Eno.of atoms x atomie weight) for Aummation .Molamax

2. 6.30x1 a ofoxalie aeid X - 6.30x to2 mort 126 5 x L04 mol oxalie adid 250mL Solution eontaining 5x10mal oxalicaud mL 5x101 250 1000 mL 22 5X ID XI000 250 -3 2 10 mal of oxalie auid The molasity of th oxaue aid Solution 210 (M)