Question

Consider the reaction N2(g) +3H2(g) 2NH3(g) Suppose that at a particular moment during the reac- tion molecular hydrogen is reacting at the rate of 0.074 M/s. (a) At what rate is ammonia being formed? (b) At what rate is molecular nitrogen reacting?

Answer 1

a)

Rate of reaction in terms H2:

Rate of reaction = (1/3)*rate of reaction of H2

Rate of reaction in terms N2:

Rate of reaction = rate of reaction of N2

Rate of reaction in terms NH3:

Rate of reaction = (1/2)*rate of reaction of NH3

So,

(1/2)*rate of reaction of NH3 = (1/3)*rate of reaction of H2

rate of reaction of NH3 = (2/3)*rate of reaction of H2

= (2/3)*0.074 M/s

= 0.049 M/s

Answer: 0.049 M/s

b)

So,

rate of reaction of N2 = (1/3)*rate of reaction of H2

rate of reaction of N2 = (1/3)*rate of reaction of H2

= (1/3)*0.074 M/s

= 0.025 M/s

Answer: 0.025 M/s