Question

10. A student heats 100 mL of water to 76 °C. The temperature of the surrounding was a constant 26 °C. The water-cooled to 34 °C after a time interval of 25 minutes. Find the time required for the water to cool from 34 °C to 24 °C. Hint: Lab environment Experiment #2

Answer 1

Hi,

Hope you are doing well.

__________________________________________________________________________

Given that,

Initial temperature of water,

Ti = 76°C

Final temperature of water,

T, = 34"

Temperature of surroundings,

T. = 26C

Time interval,

t=25 min

Applying Newton's law of cooling:

T =7; – k (T + F – z)

76 - 34 76 +34 -- 26 25 min =K

42 = 29K

42 ..K= 725

Again,Given that,

Initial temperature of water,

Ti = 34°C

Final temperature of water,

T = 24°C

Applying Newton's law of cooling:

T =7; – k (T + F – z)

- - ( 2 - 26)

10 42 t=725 X 3

10 x 725 ...t= 42 x 3 min

iit= 57.54 min

__________________________________________________________________________

Hope this helped for your studies. Keep learning. Have a good day.

Feel free to clear any doubts at the comment section.

Please don't forget to give a thumps up.

Thank you. :)