Question

A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 15.0 m/s, and the distance from the limb to the level of the saddle is 3.95 m.

(a) What must be the horizontal distance between the saddle and limb when the ranch hand makes his move? ____ m


(b) How long is he in the air? __ s

Answer 1

Solution)

Distance covered = ½ * acceleration * time^2

3.95 = ½ * 9.8 * t^2

t = 0.897 seconds (Ans- Part b)

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Now,

Distance = velocity * time

Distance = 15.0 m/s * 0.897 s = 13.46 meters (Ans- Part a)

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