Question

A stunt woman sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The speed of the horse is 14.5 m/s, and the woman is initially 2.75 m above the level of the saddle. What must be the horizontal distance between the saddle and limb when the woman makes her move?

Answer 1

Given data:

Speed of horse = 14.5 m/s

Taking acceleration due to gravity = g = 9.8 m/s^2

Concept: Time taken by women to cover 2.75 m distance from rest = Time taken by horse to cover horizontal distance.

Graphical illustration of question: Let da horizontal distance between saddle and limb, (when women make her more). Women Tree limb. H= 2.75m of Horse saddle E Horse spee = 14.5 m/s. d Women and women → As women is falling from Rest. u= initial velocity = 0. is due to gravity accelerahoon from uniform acceleration motion Equation, S = Displacement. S = ut + 1 u= initial velocity ga = 9.8 m/s2 to time (in second). i. Time Required by women 2.75 m 2.75 = 0 + 22x9.8 xt² oolt=0.749 seconds.) 2942 acceleration Cover

Now, Distance covered by horse in horizontal direction in time of 0.749 second

Distance = Speed * time

Distance =

So the horizontal distance between saddle and limb must be 10.8605 m.