Question

html Saved 10 attempts left Check my work Be sure to answer all parts. Determine the amount of heat (in kJ) associated with the production of L46 x 10g of NO, according to- the following equation: 2 NOg)+O2)2NO (g) Enter your answer in scientific notation. AH--114.6 kJ/mol x 10 kJ 2 of 2 <Prev search

Answer 1

Molar mass of NO₂=Molar mass of N+2xMolar mass of O

=14 g/mol+2x16 g/mol=14 g/mol+32 g/mol=46 g/mol

Number of moles of NO₂ to be produced

= Given mass/Molar mass

=1.46 x 10⁴ g/46 g/mol=317.39 mol

We can see that ratio of product NO₂ to reactant NO is 2:2 i.e. 1:1

So number of moles of NO required to produce given amount of NO₂=317.39 mol

Amount of heat associated with the production of given amount of NO₂ = Amount of heat associated with using 317.39 mol NO

=Number of moles x Molar enthalpy

=317.39 mol x (-114.6 kJ/mol)=-36372.9 kJ

=-36372.9 kJ x 10^-4x10⁴ kJ

=-3.63729 x 10⁴ kJ