Question

1).In a uniform circular motion, instantaneous velocity is tangent to the circle a) True b) False c) Can's say 2).In a uniform circular motion, acceleration is normal to the velocity and directed toward the center a) True b) False c) Unknown 3). For a particle of mass 'm' moving with a uniform velocity 'v' in a circle of radius 'r', write the expression for centripetal force (Fc)? 4). If a particle rotates in a circle of radius r= 10 cm with a velocity v = 1 m/s, how much acceleration it experiences toward the center? 5). An object revolving in a circular orbit and performs 10 revolution per minute. What is the frequency (f) and the period (T)? 6). For question (4), what is the angular velocity (c)? 7). Imagine you are driving in a curved road, which has a constant of static friction 0.5. Find the force of friction exerted by the road on the tire for the car of 1000 kg moving with a speed of 25 miles/hour. 8).For 20 mile/hour speed limit in a curved road of radius r = 200 m, what banking angle should be recommend in order to avoid accident. 9). What is the gravitational force between earth and an object of mass m- 10 kg lying on the earth surface? Use constants for earth mass, radius and gravitational constant as discussed. 10). The gravitational force is inversely proportional to the distance between two objects. This means the gravitational force between objects increases by decreasing the distance. a) True b) False c) Unknown

Answer 1

im niform cirular motion theinat antane ous AV velocity is tangent to thu circle a)True Accelerabon s manmal to velo citey and directed towards eente a) True Centripital force Fe mv 4 v2 7 10Cm = 0.1m V1mis ac Fc 1 10 mls ac = 1 10 TPm Argulan w velout 2x3.14x 21N 60 1OS nasys Fruqueney f 1.OS 0.17 H2 21 2x3.14 time period T = 5.88 Sec 0.17 Angular velocisy o 10 Jad (S ve25mies /hour : 25x o.A 4-704 mS 4N V= 11.18 mis frictional foree F s N 0.SXmg 0.5X100o X g.8 tr 4900 N

V: 2o mils /hour 8.94m1s 2ox o 4470 200 m we knoo that banking angle tane- V2 94)2 tano = 0.04 077 200 X9.8 0tan (o- 040 77) = 2.33 mass of object m o Kg Let earth mnass Me, Radius Re grawitationa fara F G Me m (Re)r F = 1o G Me /N ke2 gravitational foru Fa R2 if R es then F Te
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