Question

A Review | Constants Periodic Table A-10.0 nC point charge and a +20.0 nC point charge are 14.8 cm apart on the c-axis. Part A What is the electric potential at the point on the c-axis where the electric field is zero? Express your answer with the appropriate units. V = Value Units Submit Request Answer Part B What is the magnitude of the electric field at the point on the c-axis, between the charges, where the electric potential is zero? Express your answer with the appropriate units. E = Value Units Pearson

Answer 1

A)

at point P suppose E = 0

k* 10 / x² = k*20/(0.148+x)²

10 / x² =20/(0.148+x)²

from here x≈0.357304 m

and x≈-0.0613036 m ( reject )

so potential at this point

= 9*10^9* -10*10^-9 / 0.357304 + 9*10^9*20*10^-9 / (0.357304+0.148)

= 104.3348 V answer

Input interpretation: ( 10 10 +9 10° 0.357304 +0.148 9_10° 0.357304)* 2010- Enlarge Customize A Plain Text Result: 104.3348565731736302527958615951320058375064017

B) suppose electric is zero between them and it is x distance from -10 nc so

V = k*-10/ x + k*20/ ( 0.148+x) = 0

10/ x = 20/ ( 0.148-x)

from here x≈0.148 m

electric field at this location

E = 9*10^9*-10*10^-9/ 0.148^2 + 9*10^9*20*10^-9 / ( 0.148+0.148 )

= 3500.73 V/m

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