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5. A 45 g of metal at 70°C is added to 24 g of H2O at 10 °C. At equilibrium, temperature is 20 °C. What amount of heat flowed

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Answer #1

Given:

m = 24 g

C = 1 cal/g.oC

Ti = 10 oC

Tf = 20 oC

use:

Q = m*C*(Tf-Ti)

Q = 24.0*1.0*(20.0-10.0)

Q = 240.0 cal

Answer: 240 cal

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