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3. 0/1 points Previous Answers OSCol Phys2016 8.1.WA.001.Tutorial My Notes Ask Your Teacher As shown in the figure below, cars #1 and #2 are sliding across a horizontal frictionless surface. The cars are equipped with a coupling arrangement similar to the one on railroad cars. Car #1 overtakes car #2 and they have a totally inelastic collision and become coupled together. You know the mass of each car; m, -19.5 kg and m,- 49.0 kg. In addition, you are provided with the following graph, which shows the momentum of car #1 before, during and after the collision. pike m/s) 1004 Determine the velocity (in m/s) of car #2 before the collision. You have been given the mass of car #1 and the graph provides you with the momentum of the car after the collision. See if you can use this information to determine the velocity of car #1 after the collision. Knowing the velocity of car #1 after the collision and also knowing that the two cars are coupled together, see if you can determine the velocity and hence momentum of car #2 after the collision. Since momentum is conserved, how does the change in momentum of car #2 during the collision compare to the change in momentum of car #1 (obtained from the graph)? Knowing how the initial, final and change in a physical quantity are related, see if you can use this relationship to determine the initial momentum and then initial velocity of car #2. As a check on your work, see if your answers support the knowledge that momentum is conserved. m/s Additional Materials Reading ST

Answer 1

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from the graph final momentum of car 1

40 kg *m/s = 19.5*V_common

V_common = 40/19.5 =2.05128205

so this will be aslo speed of car 2 after collision becuse they they travel togther after collision

now by momentum conservation

100+ 49*Vi = ( 19.5+49)*2.05128205

from here Vi = 0.826792 m/s

so speed of car 2 before collision = 0.826792 m/s