As shown in the figure below, cars #1 and #2 are sliding across a horizontal frictionless...

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Answer 1

Answer #1

Given:

From the graph:

1. Momentum of car-1 before collision = 100Kg-m/s

2.momentum of car-1 after collision = 40 Kg-m/s

velocity of car-1 after collision = 40/14.5 m/s

Law of conservation of momentum:

m1 x v1 +m2 x v2=(m1+m2) x vf

100 +42 x v2 = (14.5+42) x 40/14.5

v2= 1.33 m/s

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Answer 2

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