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Initially, 0.64 mol of PCI, is placed in a 1.0 L flask. At equilibrium, there is 0.18 mol of PClz in the flask. What is the e
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pula 0064 M (0.64-x)M = o P Cl₂ o +&M + Clq los o ou +xm too (initially) x=0018 als id lod sodo toolt [pus dat enim = (0.64-0Hope you will like my answer.

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