What is the pH of a 0.060 M aqueous solution of calcium hydroxide?
A) 10.92 B) 1.22 C) 12.78 D) 13.08
calcium hydroxide = Ca(OH)2
Ca(OH)2 ----------> Ca+2 + 2OH-
[OH-] = 2[Ca(OH)2] = 2 x 0.060 = 0.12 M
pOH = - log [OH-]
pOH = - log [0.12]
pOH = 0.92
pH = 14 - 0.92
pH = 13.08
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