A flashlight is held at the edge of a swimming pool at a height h = 2.2 m such that its beam makes an angle of θ = 58 degrees with respect to the water's surface. The pool is d = 1.5 m deep and the index of refraction for air and water are n1=1 and n2 = 1.33, respectively.
What is the horizontal distance D, from the edge of the pool to the port on the bottom of the pool where the light strikes?
A flashlight is held at the edge of a swimming pool at a height h = 2.2 m
A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ = 41 degrees with respect to the water's surface. The pool is d = 2.25 m deep and the index of refraction for air and water are n1 = 1 and n2 = 1.33, respectively.what is the horizontal distance, D, from the edge of the pool to the point on the bottom of...
(20%) Problem 2: A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ 41 degrees with respect to the water's surface. The pool is d = 2.25 m deep and the index of refraction for air and water are n1 = 1 and n2-1.33, respectively Randomized Variables h 2.4 m d 2.25 m 6% 41 degrees What is the horizontal distance, D, from...
L. A flashlight on the bottom of a 4.00 m deep swimming pool sends a ra d at an angle so that the ray strikes the surface of the water 2.00 m fromt directly above the flashlight. What angle (in air) does the emerging ray make water's surface? (10) he point
You are standing in a 1.5-m-deep swimming pool at night. The water is very still. You hold a laser pointer just above the water's surface and shine it nearly parallel to the surface, but tilted slightly down so that the beam enters the water 3.5mfrom you. How far from you does the beam strike the bottom of the pool? Index of refraction of the water is 1.33.
A flashlight on the bottom of a 3.95 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 1.65 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
A flashlight on the bottom of a 3.93 m deep swimming pool sends a ray upward at an angle so that the ray strikes the surface of the water 1.89 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle θ = 50.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33.
Part 3. Problems (Total 50 marks) 1. A flashlight on the bottom of a 4.00 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 2.00 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface? (10) Yuwote.33 atr
In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle θ = 48.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33. Blocked Sunrays
It's nighttime, and you've dropped your goggles into a 2.8-m-deep swimming pool. If you hold a laser pointer 1.0 m above the edge of the pool, you can illuminate the goggles if the laser beam enters the water 2.2 m from the edge. How far are the goggles from the edge of the pool?