In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to...

Question

Question

In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle θ = 48.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33.

Blocked Sunrays

science physics

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

(90-0 air water IL (6-4) y shadow We have given O: 48 1.8m I 50 (M = 0.5 m 1 la 9.33 xty length of shadow = from snells law na sin (Go-o) - Mosina 1x sin (90

Add a comment

Answer 2

Similar Homework Help Questions

In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to...

In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle 0 = 52.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33. Blocked sunrays Number Units
In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to...

In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle θ = 50.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33.
In the figure, a 2.4 m long vertical pole extends am the bottom of a swimming...

In the figure, a 2.4 m long vertical pole extends am the bottom of a swimming pool to a point S cm above the water Sunlight is incident at angle theta = 52.0 degree what is the length in meters of the shadow of the pale on the lessthanorequalto bottom of the pool? The water has an index of refraction of 1.33.

A flashlight is held at the edge of a swimming pool at a height h = 2.2 m

A flashlight is held at the edge of a swimming pool at a height h = 2.2 m such that its beam makes an angle of θ = 58 degrees with respect to the water's surface. The pool is d = 1.5 m deep and the index of refraction for air and water are n1=1 and n2 = 1.33, respectively. What is the horizontal distance D, from the edge of the pool to the port on the bottom of the pool...
A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ = 41 degrees with respect to the water's surface

A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ = 41 degrees with respect to the water's surface. The pool is d = 2.25 m deep and the index of refraction for air and water are n1 = 1 and n2 = 1.33, respectively.what is the horizontal distance, D, from the edge of the pool to the point on the bottom of...
a mirror is placed perpendicular to a swimming pool water surface. a narrow beam of light...

a mirror is placed perpendicular to a swimming pool water surface. a narrow beam of light incident on the mirror is reflected on the mirror & then it follows the path shown in the figure . the angle of incidence on the mitror is θi= 36.7° . find the length (a) angle of the incidence θ2 on water surface; (b) the angle of refraction θ3 in water . (nAir = 1 and nWater= 1.33) (a) θ2= _______ (b) θ3=_______ mirror...

Grade Cate Description Policies: Light is travel from the bottom of a swimming pool to the...

Grade Cate Description Policies: Light is travel from the bottom of a swimming pool to the air above. If the angle between the surface of the water and light refraction of water is 1.3 from the bottom of the pool is 60°, what is the angle of refraction. The index of You can che You can view give up on a You can keep you get it rig You lose S% o answer in you attempt at tha degrees D...
You are standing in a 1.5-m-deep swimming pool at night. The water is very still. You...

You are standing in a 1.5-m-deep swimming pool at night. The water is very still. You hold a laser pointer just above the water's surface and shine it nearly parallel to the surface, but tilted slightly down so that the beam enters the water 3.5mfrom you. How far from you does the beam strike the bottom of the pool? Index of refraction of the water is 1.33.
(20%) Problem 2: A flashlight is held at the edge of a swimming pool at a...

(20%) Problem 2: A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ 41 degrees with respect to the water's surface. The pool is d = 2.25 m deep and the index of refraction for air and water are n1 = 1 and n2-1.33, respectively Randomized Variables h 2.4 m d 2.25 m 6% 41 degrees What is the horizontal distance, D, from...

1,-1,Casco), ) - Question 25 4 pts A mirror is placed perpendicular to a swimming pool...

1,-1,Casco), ) - Question 25 4 pts A mirror is placed perpendicular to a swimming pool water surface. A narrow beam of light incident on the mirror is reflected on the mirror and then it follows the path shown in the figure. The angle of incidence on the mirror is 0 = 36.7'. Find the (a) angle of incidence, by on water surface; (b) the angle of refraction, 0, in water. Inair - land water = 1.33) mirror water Your...

In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to...

Homework Answers

Add Answer to:
In the figure, a 1.8-m-long vertical pole extends from the bottom of a swimming pool to...

Post as a guest

Earn Coins