Question

Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol ( Δ?°′=−2870 kJ/mol ). If one contraction cycle in muscle requires 67 kJ , and the energy from the combustion of glucose is converted with an efficiency of 43% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number.

Cycles per mole glucose = ___________

thank you!

Answer 1

Page No - 0 Answer & S Given , The complete Combustion of One Mole of glucose to carbon dioxide and water liberats - 2870 kJ/mol so, Energy release for One Hole combustion of glucose = 2870 ks Efficiency = 43% - 0.43 Effective energy to be utilised = 0.43 x 2870 = 1234.1 ks One Contraction Cycle in Muscle requires energy = 67kJ How many contraction cycles theoretically possible. = 1234.1 kJ/ 6765 - 18.419 = 18.5 so, How many contraction cycles the cretically ponsible = 18.5