Equipment | Cost of old equipment (C) | Original size (Q1) | New size(Q2) |
Q=(Q2/Q1) |
Power sizing exponent (n) |
(Q)n | Cost of new equipment = C(Q)n |
Varnish bath | 3500 | 50 gal | 75 gal | 1.5 | 0.8 | 1.38 | 4830 |
Power scrapper | 250 | 0.75 hp | 1.5 hp | 2 | 0.22 | 1.16 | 290 |
Paint booth | 3000 | 3 ft3 | 12 ft3 | 4 | 0.6 | 2.3 | 6900 |
Total cost of new equipment = 4830+290+6900 = 12020$
Old equipment total cost = 6750$
Sale value of old equipment = 6750*15% = 1012.5$
Net cost to obtain new equipment = 12020-1012.5 = 11007.5$
2-48 A refinisher of antiques named Constance has beern so successful with her small business that...
2-49 Refer to Problem 2-48 and now assume the prices for the equipment that Constance wants to replace have not been constant. Use the cost index data for each piece of equipment to update the costs to the price that would be paid today. Develop the overall cost for Constance, again assuming the 15% trade-in allowance for the old equipment. Trade-in value is based on original cost. Cost Index Original When Originally Cost Index Purchased Today Equipment Varnish bath Power...