Question

In Figure (a), a uniform 42.6 kg beam is centered over two rollers. Vertical lines across the beam mark off equal lengths. Two of the lines are centered over the rollers; a 8.87 kg package of tamale is centered over roller B. What are the magnitudes of the forces on the beam from (a) roller A and (b) roller B? The beam is then rolled to the left until the right-hand end is centered over roller B (Figure (b)). What now are the magnitudes of the forces on the beam from (c) roller A and (d) roller B? Next, the beam is rolled to the right. Assume that it has a length of 0.997 m. (e) What horizontal distance between the package and roller B puts the beam on the verge of losing contact with roller A? (a) (b)

Answer 1

A)

Force, F = Mg/2 = 42.6 x 9.8/2 = 208.74 N

B)

Force, F = (208.74) + (8.87 x 9.8) = 295.67 N

C)

Force, F = (42.6 x 9.8) + (8.87 x 9.8/2) = 460.94 N

D)

Force, F = 8.87 x 9.8/2 = 43.46 N

E)

m g x = M g [(L / 4) - x]

8.87 x = 42.6 (0.997/4) - x

X = 1.08 m

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