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Question (part 1 of 3) Your respons An air-filled capacitor consists of two paral- lel plates,...
016 (part 1 of 3) 10.0 points An air-filled capacitor consists of two parallel plates, each...
016 (part 1 of 3) 10.0 points An air-filled capacitor consists of two parallel plates, each with an area of 4.65 cm, sepa- rated by a distance of 1.66 mm. A 17.7 V potential difference is applied to these plates. Find the magnitude of the electric field be- tween the plates. The permittivity of free space is 8.8542 x 10 12 c /N-m2 Answer in units of kV/m. 017 (part 2 of 3) 10.0 points Find the capacitance. Answer in...
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.80 mm. If a 17.0 V potential difference is applied to these plates, calculate the following. (a) the electric field between the plates _______ kV/m (b) the capacitance _______ pF (c) the charge on each plate _______ pC
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 25.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nC/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pC
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. A 25.0-V potential difference is applied to these plates (a) Calculate the electric field between the plates kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate pc
003 (part 1 of 2) 10.0 points Consider an air-filled parallel plate capacitor with plate area...
003 (part 1 of 2) 10.0 points Consider an air-filled parallel plate capacitor with plate area A and gap width d and plate charge What is the total energy stored in the ca pacitor? 2 0 A Eo d Eo A d 2 0 A d 4. U = 004 (part 2 of 2) 10.0 points With the battery connected, fill the gap by a slab with the dielectric constant 3.6. If the potential is 30 V, the plate sep-...
Solve for a and b and show work please. An air-filled parallel-plate capacitor has plates of...
Solve for a and b and show work please.
An air-filled parallel-plate capacitor has plates of area 3.00 cm2 separated by 0.50 mm. The capacitor is connected to a 3.0-V battery. (a) Find the value of its capacitance. 0.531 Your response is off by a multiple of ten. p (b) What is the charge on the capacitor? 1.59 Your response is off by a multiple of ten. pc (c) What is the magnitude of the uniform electric field between the...
Part A With vacuum between its plates, a parallel-plate capacitor has capacitance 4.50 pF. You attach...
Part A With vacuum between its plates, a parallel-plate capacitor has capacitance 4.50 pF. You attach a power supply to the capacitor, charging it to 320 kV, and then disconnect it. You then insert a dielectric sheet that fills the space between the plates. The potential difference between the plates decreases to 1.60 kV, and the charge on each plate remains constant. Find the energy stored in the capacitor before you insert the sheet Express your answer with the appropriate...
Question (part 1 of 2) Your respons Calculate the resistance per unit length of a nichrome...
Question (part 1 of 2) Your respons Calculate the resistance per unit length of a nichrome wire, which has a radius of 0.115 mm. The resistivity of nichrome is 1.5x 10-6 Ω . m. Answer in units of Ω/m Question (part 2 of 2) Your response.. If a potential difference of 15 V is main tained across a 5.3 m length of the nichrome wire, what is the current in the wire? Answer in units of A
A parallel-plate capacitor filled with air has plates of area 7.0×10−3 m2m2 and a separation of...
A parallel-plate capacitor filled with air has plates of area 7.0×10−3 m2m2 and a separation of 0.32 mmmm . A) Find the magnitude of the charge on each plate when the capacitor is connected to a 12-VV battery. b) Will your answer to part A increase, decrease, or stay the same if the separation between the plates is increased? c) Explain. d) Calculate the magnitude of the charge on the plates if the separation is 0.90 mmmm .
IP A parallel-plate capacitor filled with air has plates of area 6.5×10−3 m2 and a separation...
IP A parallel-plate capacitor filled with air has plates of area 6.5×10−3 m2 and a separation of 0.32 mm. Find the magnitude of the charge on each plate when the capacitor is connected to a 12-V battery. Will your answer to part A increase, decrease, or stay the same if the separation between the plates is increased? Calculate the magnitude of the charge on the plates if the separation is 0.90 mm .
016 (part 1 of 3) 10.0 points An air-filled capacitor consists of two parallel plates, each with an area of 4.65 cm, sepa- rated by a distance of 1.66 mm. A 17.7 V potential difference is applied to these plates. Find the magnitude of the electric field be- tween the plates. The permittivity of free space is 8.8542 x 10 12 c /N-m2 Answer in units of kV/m. 017 (part 2 of 3) 10.0 points Find the capacitance. Answer in...
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 25.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nC/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pC
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. A 25.0-V potential difference is applied to these plates (a) Calculate the electric field between the plates kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate pc
003 (part 1 of 2) 10.0 points Consider an air-filled parallel plate capacitor with plate area A and gap width d and plate charge What is the total energy stored in the ca pacitor? 2 0 A Eo d Eo A d 2 0 A d 4. U = 004 (part 2 of 2) 10.0 points With the battery connected, fill the gap by a slab with the dielectric constant 3.6. If the potential is 30 V, the plate sep-...
Solve for a and b and show work please.
An air-filled parallel-plate capacitor has plates of area 3.00 cm2 separated by 0.50 mm. The capacitor is connected to a 3.0-V battery. (a) Find the value of its capacitance. 0.531 Your response is off by a multiple of ten. p (b) What is the charge on the capacitor? 1.59 Your response is off by a multiple of ten. pc (c) What is the magnitude of the uniform electric field between the...
Part A With vacuum between its plates, a parallel-plate capacitor has capacitance 4.50 pF. You attach a power supply to the capacitor, charging it to 320 kV, and then disconnect it. You then insert a dielectric sheet that fills the space between the plates. The potential difference between the plates decreases to 1.60 kV, and the charge on each plate remains constant. Find the energy stored in the capacitor before you insert the sheet Express your answer with the appropriate...
Question (part 1 of 2) Your respons Calculate the resistance per unit length of a nichrome wire, which has a radius of 0.115 mm. The resistivity of nichrome is 1.5x 10-6 Ω . m. Answer in units of Ω/m Question (part 2 of 2) Your response.. If a potential difference of 15 V is main tained across a 5.3 m length of the nichrome wire, what is the current in the wire? Answer in units of A
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