Question

1. Given the following reaction N2(g) + 3H2(g) → 2NH3(e) (a) How many number of moles of ammonia can be formed from 0.25 moles of N, gas?

Answer 1

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No (g) + 3H₂(g) - 2NH₂ (9) 1 mol 2 mot mol (a) 1 mole N₂ gas Produce = 2 mole NH3 Now 0.25 mole Ne gas Roduce = 2x0.25 mol NH3 = 0.5 mol NH3 Ans 0.5 moles of NH3 6 Imole N2 React with = 3 Now 0.25 mole N₂ React with mole of H₂ = 3x0.25 mole A₂ - 0.75 mol 12 Ang – 0.75 mole of He needed We know that iven mole of N₂ = 2 mole of H2 =3 mot Ny required - 3 mol H₂t ar 2 mol N2 4 = 6 mol H2 But we have only 3 mole H₂ which is less than required mot so te is limiting Reagent, Now He Reagent decide the amount of NH3 3 mof the Produce = 2 mol Nuz M are not fully used let Amount = I mot N₂ = 20 gram & obtained 2 mol of NH3