Question

1. Given the following reaction N2(g) + 3H2(g) → 2NH3(e) (a) How many number of moles of ammonia can be formed from 0.25 mole
(b) How many moles of H, are needed to react with 0.25 moles of N, gas? If you begin with a gas mixture that contains 2.00 mo
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Answer #1

thank you very much .hope this will help you .good luckNo (g) + 3H₂(g) - 2NH₂ (9) 1 mol 2 mot mol (a) 1 mole N₂ gas Produce = 2 mole NH3 Now 0.25 mole Ne gas Roduce = 2x0.25 mol NH

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