How many moles of NH3 can be produced from 3.25 moles of nitrogen in the following reaction?
N2 + 3H2 --> 2NH3
From the balanced equation we can say that
1 mole of N2 produces 2 mole of NH3 so
3.25 mole of N2 will produce
= 3.25 mole of N2 *(2 mole of NH3 / 1 mole of N2)
= 6.50 mole of NH3
Therefore, the number of moles of NH3 produced would be 6.50
How many moles of NH3 can be produced from 3.25 moles of nitrogen in the following reaction? N2 + 3H2 --> 2NH3
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