Question

Question 6 1 pt Consider a molecule of SF4, and determine if each of the following statements is True or False. 1) In the best Lewis structure, the central atom satisfies the octet rule. [ Select] 2) The molecular geometry and the electron geometry are the same. [ Select) 3) The S-F bonds are polar covalent. [Select] 4) It is a nonpolar molecule. (Select] 5) The hybridization scheme around the central atom is sp. (Select)

Answer 1

Ans. 1) In lewis structure sulphur has 6 valence shell electrons and after sharing with 4 flourine atoms it has total 10 electron. So it does not satisfy octet rule.

Ans 2) This molecule has 4 bond pairs and 1 lone pair electrons. Out of 4 bond pairs, the angle between two is 180 and other two has around 120 degree angle. Due to which it has a see-saw molecular geometry. In case electron geometry there is also a lone pair due to which it has a trigonal bypyrmidal shape. So the above statement is false because SF₄ has different molecular and electron geometry.

Ans.3) Flourine is more electronegetive than Sulphur. So their is a charge separation between S-F bond. Due to which the bond becomes polar. Hence the statement is true.

Ans.4) As discussed in above (ans. 2) their are 2 bond angles in molecule 180 and 120 degree.The bond angle 120 results in a net dipole moment. Due to which the molecule becomes polar and the above statement is false.

Ans.5) The central atom sulphur has electronic configuration 3s² 3p⁴ . The 2 s-orbital electrons remain as a lone pair and 1 out of 4 p-orbital elecrtron shifts to d-orbital to make avaiblity of 4 unpaired electrons to share with 4 flourine atoms. Therefore the hybridisation of this molecule is sp³d. So the above statement is false.