1)
Molar mass of HCl,
MM = 1*MM(H) + 1*MM(Cl)
= 1*1.008 + 1*35.45
= 36.458 g/mol
mass of HCl = 9.19 g
mol of HCl = (mass)/(molar mass)
= 9.19/36.458
= 0.2521 mol
According to balanced equation
mol of H2 formed = (1/2)* moles of HCl
= (1/2)*0.2521
= 0.1260 mol
Answer: 0.1260 mol
Only 1 question at a time please
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