Hydrogen gas can be prepared by reaction of zinc metal with
aqueous HCl:
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)
How many grams of zinc would you start with if you wanted to prepare 5.05 L of H2 at 260 mm Hg and 26.0 Celsius?
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many grams o...
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many liters of H2 would be formed at 680 mm Hg and 17 ∘C if 27.0 g of zinc was allowed to react? How many grams of zinc would you start with if you wanted to prepare 6.00 L of H2 at 400 mm Hg and 35.0 ∘C?
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) Part A: How many liters of H2 would be formed at 538 mm Hg and 16∘C if 22.0 g of zinc was allowed to react? Part B: How many grams of zinc would you start with if you wanted to prepare 5.65 L of H2 at 350 mm Hg and 34.5 ∘C?
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 2.00 M HCl(aq)2.00 M HCl(aq) are required to react with 8.55 g Zn(s)?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.00 M HCl(aq) are required to react with 2.65 g of an ore containing 26.0 % Zn(s) by mass? volume: mL
Hydrogen gas is produced by the reaction of hydrochloric acid, HCl, on zinc metal. 2HCl (aq) + Zn (s) --> ZnCl2 (aq) + H2 (g) The gas is collected over water. If 106 mL of gas is collected at 28C and 775 mmHg, what is the mass of hydrogen collected? (vapor pressure of water at 28C is 25.6 mmHg)
Q2 part1. Hydrogen gas can be readily prepared by reacting zinc metal with hydrochloric acid: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) A sample of zinc metal was decomposed in hydrochloric acid and the hydrogen gas was collected over water. The volume of gas collected is 0.798 L at 25oC and a total pressure of 735 torr. How many grams of zinc were decomposed assuming there is an excess of hydrochloric acid? [Hint: the vapor pressure of water at 25oC...
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 3.50M HCl(aq) are required to react with 2.65g of an ore containing 41.0% Zn(s) by mas
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 6.50 M HCl(aq) are required to react with 4.45 g of an ore containing 39.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 4.00 M HCl(aq) are required to react with 7.15 g of an ore containing 43.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.50 M HCl(aq) are required to react with 2.95 g of an ore containing 43.0 % Zn(s) by mass?