Hydrogen gas is produced by the reaction of hydrochloric acid, HCl, on zinc metal. 2HCl (aq)...
Hydrogen gas is produced by the reaction of hydrochloric acid, HCl, on zinc metal.
2HCl (aq) + Zn (s) --> ZnCl2 (aq) + H2 (g)
The gas is collected over water. If 106 mL of gas is collected at 28C and 775 mmHg, what is the mass of hydrogen collected? (vapor pressure of water at 28C is 25.6 mmHg)
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Hydrogen gas is produced by the reaction of hydrochloric acid,
HCl, on zinc metal.
2HCl (aq)...
A sample of zinc metal is allowed to react completely with an excess of hydrochloric acid:...
A sample of zinc metal is allowed to react completely with an excess of hydrochloric acid: Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(8) look GO The hydrogen gas produced is collected over water at 25.0°C. The volume of the gas is 8.90 L, and the atmospheric pressure is 0.951 atm. Calculate the amount of zinc metal in grams consumed in the reaction. rint rences (Vapor pressure of water at 25°C = 23.8 mmHg.) gZn
Q2 part1. Hydrogen gas can be readily prepared by reacting zinc metal with hydrochloric acid: Zn(s)...
Q2 part1. Hydrogen gas can be readily prepared by reacting zinc metal with hydrochloric acid: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) A sample of zinc metal was decomposed in hydrochloric acid and the hydrogen gas was collected over water. The volume of gas collected is 0.798 L at 25oC and a total pressure of 735 torr. How many grams of zinc were decomposed assuming there is an excess of hydrochloric acid? [Hint: the vapor pressure of water at 25oC...
zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation:...
zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq)ZnCl2(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 745 mm Hg. If the wet H2 gas formed occupies a volume of 9.32 L, the number of moles of Zn reacted was __mol. The vapor pressure of water is 17.5 mm Hg at 20 °C.
When 0.40 g of impure zinc reacted with excess hydrochloric acid, 127mL of hydrogen gas were...
When 0.40 g of impure zinc reacted with excess hydrochloric acid, 127mL of hydrogen gas were collected over water at 10 degrees C at a total pressure of 737.77 Torr. The vapor pressure of water at 10 degrees C is 9.21 Torr. The reaction in question is: Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (aq) A.) what amount (in grams) of H2 gas was collected? B.) what is the percentage of purity of the zinc, assuming that...
Hydrogen gas is produced by the reaction of hydrochloric acid on zinc metal: Zn (s) +...
Hydrogen gas is produced by the reaction of hydrochloric acid on zinc metal: Zn (s) + HCl (aq) --> ZnCl (aq) + H2 (g) If 155ml of gas was collected at 26℃ and the total pressure was 1.12 bar how many milli-moles (mmol) of hydrogen was produced? Vapour pressure of water at 26℃: 0.0233 barr, R = 0.08314 L*bar/mol*K MM's: Zn = 65.39 g/mol, H = 1.008 g/mol, Cl = 35.35g/mol
In a water displacement experiment, a student used a reaction of solid Zn with hydrochloric acid...
In a water displacement experiment, a student used a reaction of solid Zn with hydrochloric acid (Zns + 2HCl(aq) = ZnCl2(aq) + H2(g)) and collected 1.72 L of gas at 745.72 mmHg and 25◦C. 1. How much hydrogen gas (in moles) was produced? At 25◦C, vapor pressure of water is 23.78 mmHg. 2. How much Zn, by mass, was used in this reaction?
Hydrogen gas was produced by reacting 0.976 g of zinc metal with excess hydrochloric acid. Write...
Hydrogen gas was produced by reacting 0.976 g of zinc metal with excess hydrochloric acid. Write a balanced reaction equation (include states). If 376 mL of hydrogen gas is collected over water at 25 °C at a total pressure of 751 mm Hg, what was the experimental molar mass of Zn? 1. Write a balanced reaction equation (include states). 2. What was the experimental molar mass of Zn? Answer to the correct number of significant figures. 3. Calculate the %...
Zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation:...
Zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq)>ZnC2(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 749 mm Hg. If the wet H2 gas formed occupies a volume of 8.34 L, the number of grams of H2 formed is g. The vapor pressure of water is 17.5 mm Hg at 20 cc. Submit Answer Retry Entire Group...
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many grams o...
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many grams of zinc would you start with if you wanted to prepare 5.05 L of H2 at 260 mm Hg and 26.0 Celsius?
please help Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) +2HCl(aq) ? ZnCl2(aq)-H2(g...
please help
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) +2HCl(aq) ? ZnCl2(aq)-H2(g How many milliliters of 4.50 M HCl(aq) are required to react with 5.25 g of an ore containing 50.0% Zn(s) by mass? Number mL
A sample of zinc metal is allowed to react completely with an excess of hydrochloric acid: Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(8) look GO The hydrogen gas produced is collected over water at 25.0°C. The volume of the gas is 8.90 L, and the atmospheric pressure is 0.951 atm. Calculate the amount of zinc metal in grams consumed in the reaction. rint rences (Vapor pressure of water at 25°C = 23.8 mmHg.) gZn
Zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq)>ZnC2(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 749 mm Hg. If the wet H2 gas formed occupies a volume of 8.34 L, the number of grams of H2 formed is g. The vapor pressure of water is 17.5 mm Hg at 20 cc. Submit Answer Retry Entire Group...
please help
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) +2HCl(aq) ? ZnCl2(aq)-H2(g How many milliliters of 4.50 M HCl(aq) are required to react with 5.25 g of an ore containing 50.0% Zn(s) by mass? Number mL
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