Question

molar concentration is 0.185 mol/L

Arions Date Lob Sec. Name Desk No. secend A. Preparation of Vinegar Sample Calculate the approximate volume of the vinegar sample needed for the analyses (Part A.1) Sin o (asmilo.1ok) v (o.8326) VE 3.0m2 Sivf Sos . 8326 mol Mo,8326o 0.832 mok give aab ns Kroyer vinegar Brand of vinegar or unknown no Trial 1 Trial 2 Trial 1 Trial 2 28.a31 A.os8glo9.2 91.2052 726787 5.5 .9816 S0203y 8&155 Nolar 14y of a0H- 3.0g 13.30 mL 2650m 13.3om 24.60ml 38.Som 1. Mass of flask (g) 2. Mass of flask +vinegar (e) 3. Mass of vinegar (g) B. Analysis of Vinegar Sample 6.0Lmt 1. Buret reading of NaOH, initial (mL) 2. Buret reading of NaOH, final (mL) 13, 24ml A mt m Volume of NaOH used (mL) 3. 4. Molar concentration of NaOH (molL) 5. Moles of NaOH added (mol) 6. Moles of CH,COOH in vinegar (mol) 7. Mass of CH,COOH in vinegar () 8. Percent by mass of CH,COOH in vinegar (%) 9. Average percent by mass of CH,COOH in vinegar (%) Calculations for Trial 1 of the first vinegar sample on next page. Experiment 10 147

Answer 1

Trial 1° Trial 2 Molarity of NaOH = 10-185 md 1.. CHCOOH + NaOH Moles of NaOH added & 246*03 20448103 CHCOONa+ H2O Moles of AcOH - 2.4610-3 2.44x103 . I mode of Acetic Acid Maws of AcOHS, 0:489 . 01969. Renate with i malef %. By Manageme to). 4-29). CentenoModen Maus & Cucoil Alecrioge 7. B, Marisol f1837496) 60-0529/rol NaOH 2

For Another Trial (Trial 1 in right Side)

Moles of NaOH added = Moles of AcOH = 2.22 x 10^-3

Mass of AcOH = 0.133 g.

% Mass of AcOH = 4.63%