Question

ling Chapters 14,15 Lauryn Schubert ana College - PHYS 151 - Fall19 - WETZEL > Activities and Due Dates > Chapters 14,15 re: 4713/5200 Resources Ex Give Up? Feedback Resum Attem To treat a burn on his hand, a person decides to place an ice cube on the burned skin. The mass of the ice cube is 14.4 g, and its initial temperature is -14.1 °C. The water resulting from the melted ice reaches the temperature of his skin, 28.8 *C. How much heat is absorbed by the ice cube and resulting water? Assume that all of the water remains in the hand. Constants for water can be found in this table. 2.17 X106

Answer 1

Step 1: Heat required to raise the temperature of ice from -14.1 °C to 0 °C Use the formula

q = mcΔT

where
q = heat energy
m = mass
c = specific heat
ΔT = change in temperature

q1 = 14.4*2.09*14.1 =424.3536 J

Step 2: Heat required to convert 0 °C ice to 0 °C water

Use the formula for heat:

q = m·ΔH_f

where
q = heat energy
m = mass
ΔH_f = heat of fusion

q2 = 14.4*334 =4809.6 J

Step 3: Heat required to raise the temperature of 0 °C water to 28.8 °C water

q3 = mcΔT

= 14.4*4.18*28.8 =1733.5296 J

so total heat required = q1+q2+q3 = 424.3536 +4809.6 +1733.5296 =

= 6967.4832 J answer

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