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Be sure to answer all parts. Write the half-reactions for the following redox reaction: 2Li + H2 → 2LiH Oxidation: Reduction:
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Answer #1

1)

Li in reactant has oxidation state of 0

Li in product has oxidation state of +1

So, Li is getting oxidised.

The oxidation reaction is:

Li -> Li+ + e-

2)

H in reactant has oxidation state of 0

H in product has oxidation state of -1

So, H is getting reduced.

The reduction reaction is:

H2 + 2e- -> 2 H-

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