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Station 2: Calculations with the Ideal Gas Law A Station Letter: A student reacted a strip of magnesium metal with 4.00 mL of
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Answer #1

Pressure corrected:

P H2 = P total - P H2O = 750.1 - 23.8 = 726.3 mmHg

H2 volume: 4 mL

H2 Moles:

n H2 = P * V / R * T = (726.3 / 760) * 0.004 L / 0.082 * 298 = 1.6x10 ^ -4 mol

The balanced chemical reaction is:

Mg + 2 HCl = MgCl2 + H2

Mg mass is calculated:

m Mg = 1.6x10 ^ -4 mol H2 * (1 mol Mg / 1 mol H2) * (24.3 g Mg / 1 mol) = 0.004 g

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