Calculate the temperature, in K, of 2.20 moles of gas occupying 3.50 L at 3.30 atm.

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Answer 1

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Answer #1

Moles of gas n = 2.20 mol

Volume V = 3.50 L

Pressure P = 3.30 atm

Molar gas constant R = 0.08206 atm.L/mol.K

Ideal gas equation: PV = nRT

Temperature T = PV/nR

= 3.30 x 3.50/(2.20 x 0.08206)

= 64.0 K

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Answer 2

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