Question 6
Here let say the transmitter has send the message so here
Pr(Receiving ) = p
Pr(Receiving any other particular message) = (1 - p)/(n-1)
(a) So here probability of reciving at the
receiver is to be evaluated.
Any message can be send with probability 1/n
so here we will receive when
transmitted message is
and we
received the correct message or we were transmitted any message
other than
and we
received
.
Pr(recieiving ) =
Pr(Transmitted
) *
Pr(Received
) +
Pr(Transmitted other than
) *
Pr(Recieved
)
= 1/n * p + (n-1)/n * (1-p)/(n-1)
= p/n + (1-p)/n = 1/n
(b) Now we received at the
reciever so
here
Probability that transmitted message is =
(p/n)/(1/n) = p
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