(a) How much heat transfer (in kcal) is required to raise the temperature of a 0.600...

Question

Question

Answer 1

Answer #1

A)

Q = (m1 C1 dT1) + (m2 C2 dT2) + (m1 L)

Q = (3 x 1 x 80) + (0.6 x 0.215 x 80) + (0.6 x 539)

Q = 573.72 kcal

B)

Time, t = 573.72 (4186/600) = 4 x 10^3 sec

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Answer 2

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