Specific heat capacity of water is 4.2 J/g oC.
So, for 1 gram water, to rise temperature by 1oC it needs 4.2 J heat.
Hence, for 11.1 g water, to rise temperature by 1oC it will need (4.2×11.1)J = 46.62 J heat.
Now, raising 1oC needs 46.62 J heat ( for 11.1g)
Hence, raising (175-(-45)) oC = 220oC will need (46.62×220) J = 10256.4 J heat = 10.2564 kJ heat.
Now, 1 kJ = 0.239 kcal
Hence, 10.2564 kJ = (0.239×10.2564)= 2.45 kcal.
Hence, the heat required is = 2.45 kcal.
heat in terms of kcals not kJ How much heat is required to raise the temperature...
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