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his Question: 1 pt 1 of 6 (1 complete) This Quiz: 6 pts pos Question Help Assume that thermometer readings are normally distributed with a mean of O°C and a standard deviation of 1.00°C. A thermometer is randomly selected and lested. For the case below draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 0.25 and 1.50 OB C. a, 2-0 25 21.50 025 -1.50 025 2-1. The probabilty ot getting a reading between 025°C and 150C i-O (Round to four decimal places as needed.) Click to select your answers). Next. s Previous MacBook Air 800 F
NEGATIVE Z SCores Standard Normal ()Distr ibution: Cumulative Area from the LEFT 03 07 -3.50 lower 000 -34 0o03 0003 0003 0003 0003 0003 0003 0003 0003 0002 -33 0005 0005 0005 0004 0004 0004 0004 000400040003 0007 000700060006 0006 0006 0006 005 00050005 --32 0013 00130012 0012 oom oon 0010 0010 -3.0 -2.8 -2.6 0013 -29 001s 0018 00180017 06 0016 001s 0 00140014 0026 .002s oo24 .0023 .0023 ,oo22 0021 0021 ,0020 DOS -27 0035 0034 0033 0032 03 0030 0029 0028 0027 0026 00470045 00440043 0041 0040 0039 038 0037 0036 -25 0062 0060 0059 0057 0055 0054 0052 0051 0049 0048 -2.4 0082 0080 0078 0075 0073 0071 0069 0068 4 .00660064 -23 01070104 0102 0099 096 0094 0091 0089 0087 0084 0136 0132 0129 0125 0122 o113 0110 -22 -21 01790174017001660162 0158 0154 015001460143 01920188 0183 -20 0228 0217 0212 02070202 0197 -1.9 |0287 .0281 0274 .0268 .0262 ,02SS .02S。.0244 .0239 .0233 -17 |.0446 .0436 0427 .0418 .0409 .0401 .0392 .0384 |.0375 o367 -15 | 0668 0655 0643 .0630 .0618수.0606 .0594 .0s821.os71 .0559 一1.31.0968 D9S .0934 .0918 o901 |.0885 .0869 oes3 |0838 0823 0359035 0344 03360329 0322 0314 03070301 0294 -16 05480537 0526 0516 050S 0495 0485 0475 0465 0455 0808 0793 0778 07640749 0735 0721 075 1056 038 1446 0708 0694 ,0601 1093 020 1003 0985 ,1587 1539 1515 1492 1469 1401 -a9 | .1841 J814 .1788 1762 1736 |1711 ง685 ,1660 |363S ISTI 1894 ·1867 -0724202389235823272296 226622362206 2177 2148 24832451 S308530S0 301529812946291228772843 28102776 -0.41.3446 .3409 .3372 ·3336 ·300|3264 .3228 .3792 |.3156 3121 03 38213783374537073669 3632 3594 35573520 3483 4207 41684129 4090 4052 4013 3974 3936 3897 3859 -o46024562 4522 44834443 440443644325 4286 247 4721 681464 -0.8 2090 20612033 2005 1977 949 0.6 2743 .2709 .2676 2643 .2611 25782546 2514 -0.2 5000 49604920 4880 840 4801 4761 NOTE: For values of z below-3.49, use o 0001 for the area. Use these common values that result from interpolation: z score Area 1645 00500 -2575 0.0050
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Answer #1

Given:

μ=0

sigma =1

As we have to find the probability of reading falling between 0.25 and 1.50, we have to calculate the area under the normal curve between z=0.25 and z=1.50. Thus 'A' is the correct plot. To find the required probability:

P(0.25 <= x <= 1.50)

0.25-0 1.50-0

P(0.25 <-<= 1.50)

P(z <= 1.50)-P(z <= 0.25)

0.9332-0.5987-0.3345 (see how to get these values from the table in the images attached below)

Thus the required answer is 0.3345.

P(z=0.25) = 0.5987 (see in image below)

Standard Normal Probabilities Table entry Table entry for z is the area under the standard normal curve to the left of z 01 02 03 04 05 06 07 08 09 0.0 .5000 .5040 .5080 .5120 .5160 .5199.5239 .5279 .5319 .5359 0.1 5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.2 .5793 .5832 .5871 .5910 .5948 5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 6255 .6293 .6331 6368 6406 64436480.6517 0.4 .6554 .659 .6628 .6664 6700 .6736 6772 6808 .6844 .6879 0.5 .6915 .6950.6985.7019 .7054 .7088 .7123 .7157 .7190 .7224 0.6 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486.7 0.7 .7580 .7611 .7642.7673 .7704 .7734 .7764 .7794 .7823 .7852 0.8 .7881 .7910 .7939.7967 .7995 .8023 .8051 .8078 .8106 .8133 0.9 .8159 .8186 .8212 .8238 8264 8289 .8315 .8340 .8365 .8389 1.0 8413 .8438 .8461 8485 .8508 8531 8554 .8577 .8599 .8621 517 .7549

P(z=1.50) = 0.9332 (see in image below)

Table entry Table entry for z is the area under the standard normal curve to the left of z. 0.0 .5000 5040 .5080 5120 5160 5199 .5239 5279 5319 5359 0.1 .5398 .5438 .5478 .5517 .5557 .5596 5636 .5675 .5714 .5753 0.2 .5793.5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 6368 64066443 .6480 .6517 1 3 5 6664 .6700 6736 6772 6808 .6844 0.5 .6915 .6950 .6985 .7019.70547088 .7123 .7157 .7190 .7224 0.6 .7257.7291 .7324 .7357.7389 7422 .7454 .7486.7517 .7549 0.7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852 0.8 7881 7910 .7939 7967 .7995 8023 8051 8078 .8106 3 1 8 8485 8508 8531 8554 8577 .8599 1.1 8643 8665 .8686 .8708.8729 .8749.8770 .8790 .8810 .8830 .9015 1.3 .9032 .9049 .9066 .9082 .9099 .9115 .9131 .9147 16 177 1.4 .9192 .9207.9222 .9236 .9251 .9265 .9279.9292 .9306 .9319 1.5 .9332 .9345 .9357 .9370 9382 .9394 9406 .9418 9429 .9441 .9545 88888907 8925 8944 8962 .8980 .8997 6 9452 9463 9474 9484 9495 .9505 .9515 .9525 9535

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