17. What volume of 0.0100 M NaOH must be added to 1.00 L of 0.0500 M...
What volume, in mL, of 2.00 M HCl must be added to 1.00 L of a 0.100 M solution of sodium formate, Na+HCOO-, to produce a buffer solution having a pH = 4.00? (Ka HCOOH = 1.9 x 10-4) A. 17 B. 1.9 C. 34 D. 30 E. 3.5
How many grams of solid NaOH must be added to 1.00 L of 2.0 M CH3COOH (acetic acid) to produce a solution that is buffered at each pH? Ka = 1.76 × 10–5 a. pH = pKa b. pH = 4.00
What volume of 5.50 M NaOH must be added to 470.0 mL of a buffer that is 0.0200 M acetic acid and 0.0230 M sodium acetate to raise the pH to 5.75? Ka = 1.76 x 10-5.
How much 10.0 M HNO3 must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH to 4.60 ?
What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 4.00? Ka = 1.8×10-5
2. Calculate the pH expected for the following monoprotic substances. a. HCl (strong acid) 0.0100 M 0.100 M 0.0500 M 0.00100 M b. NaOH (strong base) 0.100 M 0.0500 M 0.0100 M Experiment 4 с. НС2Н3О2 (weak acid) (Ka 1.8 x 10-5) 0.100 M 0.0500 M 0.0100 M d. K2CO3 (weak base) (K, = 2.1 x 10-4) 0.100 M 0.0500 M 0.0100 M
2. Calculate the pH expected for the following monoprotic substances. a. HCl (strong acid) 0.0100 M 0.100...
what is the pH of a titration if 12.5 mL of 0.0500 M NaOH solution is added to 40.00 mL of 0.100 M solution of nitrous acid (HNO2) Ka=6.0 x 10-4?
what mass of NaOH(s) must you add to a 1.00 L sample of 0.115 M acetic acid(which the Ka=1.8 x 10^-5) to produce a solution with a pH of 3.25?
Given a 1.00 L solution that is 0.60 M HF and 1.00 M KF, calculate the pH after 0.060 mol NaOH is added, and calculate the pH after 0.20 mol HCl is added to the original solution. Ka = 7.2x10-4 pH = when NaOH is added pH = when HCl is added
What volume (in mL) of 0.150 M NaOH must be added to 100.0 mL of a 0.0500 F solution of fumaric acid (trans-butenedioic acid) to make a buffer of pH 4.50? Ka1 of Fumeric acid = 8.85x10^-4 pKa = 3.05 Ka2 of Fumeric acid = 3.21x10-5