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17. What volume of 0.0100 M NaOH must be added to 1.00 L of 0.0500 M HOCI to achieve a pH of 8.00? Ka for HOCI is 3.5 x 10-8
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Answer #1

let volume added is a Alumbes of moles of NaOH = 0.0100 % mil Number of moles of Hoce = 0.0500 mol - NaOH + 0.0100n Hocl 0.05

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