Question

8 The plot of NH2 vs. % Al will be a straight line. To fix the position of a straight line it is necessary t least three points. The way to do this is to find when % AL=0,%AI - 25,%AI -50. %Al = 75 and when % Al = 100. All these points should lie on the same straight line 2. Sample data for this experiment. Fill in the blanks in the data and make the indicated calculation 1 Mass of capsule plus alloy sample 0.3432 g 2 Mass of gelatin capsule 0.1284 g 3 Mass of alloy sample (#1 - #2) 4 Mass of beaker and displaced water 368.910 g 5 Mass of empty beaker 144.502 g 6 Mass of displaced water (#4 - #5) 7 Barometric pressure 745.0 mm Hg 8 H2O Vapor pressure at 22.0°C 19.8 mm Hg 9 Pressure of H2 (745.0 mm - 19.8 mm) mm Hg 10 Pressure of H2 in atmospheres atm 11 Density of displaced water 0.99823 g/mL 12 Volume of displaced H2O (mass + density) mL 13 Volume of H2 = Volume of displaced H2O mL 14 Volume in liters 15 Ambient temperature 22.0°C 16 Ambient temperature in Kelvin Find the number of males of Hanoina DVI-DT -MINT

Answer 1

calculating number of mole of H2 per gram of sample

3 (llamoosso) (10.01.2018) ---- 100- 0 + 0.0153 1 at 0% A1 10 = 0.0556 (100 nx = 0.00+0.0153 ny, = 0.0153 mol/g 100 at 25% A1 *** (16-00950)- (1072540.018) nge =0.0139+0.011475 ny, = 0.0254 mol/g

at 50% A1 12 - (20-00550)+(190.50 -0.018) ny, = 0.0278 +0.00765 ny, = 0.0354 mol/g at 75% A1 mu:- (176 -0.0550)+(10:25 <0.018) nye =0.0417 +0.003825 Ny = 0.0455 mol/g at 100% A1 nu: -(100 <0.0556)+ (10960040.0153) ng, = 0.0556+0.00 ny, = 0.0556 mol/g

Now drawing a graph we get a straight line

0.06+ 01054 bout 0.03 0.027 oor 20 80 100 123 40 60 ZAL

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