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Prelaboratory Assignment: Analysis of an Aluminum-Zinc Alloy

having a difficult time figuring out how to tackle the following:
Name: Date: Section: Prelaboratory Assignment: Analysis of an Aluminum-Zinc Alloy 1. On the following page, construct a graph
Analysis of an Aluminum-Zinc Alloy (Advance Study Assignment) 0.05 0.04 0.03 Moles H, 0.02 0.01 23% 73% 50% Percent Aluminum
please help! thank you.

equation 5 is included in here
ANALYSIS OF AN ALUMINUM-ZINC ALLOY INTRODUCTION An alloy is a homogeneous mixture of two metals and is often described as a t
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Answer #1

From data :

1. eq (5) NH2 = ((% Al/100)*0.0556)+(100 - % Al/100)*0.0153))

(NH2 , is No. of moles of hydrogen produced per g of sample)

  • For 0% Al = 0.0153 mole
  • For 25% Al = 0.0254 mole
  • For 50% Al = 0.0355 mole
  • For 75% Al = 0.0455 mole
  • For 100% Al = 0.0556 mole

You can construct NH2 vs % Al graph using these data.

% Al vs Moles of H2 0.06 0.04 Moles of H2 25 50 75 100 % of Al

2.

  • Mass of Alloy = 0.3522 g -0.1168 g = 0.2354 g
  • mass of water = 388.3 g -141.2 g = 247.1 g
  • volume of water = 247.1 g /0.998 g/ml = 247.6 ml (density of water = 0.998 g/ml )
  • temperature = 294.15 K
  • Vapour pressure of water = 18.7 mm Hg (@ 21 C)
  • Now you need data from lab, volume of water displaced you will get Volume of Hydrogen. From volume of Hydrogen you can calculate moles of Hydrogen evolved : 1mol = 22.4 litres (at 273.15 K) Since V1/T1 = V2/T2

Volume of 1 mol at 294.15 K : 22.4 L *294.15 K / 273.15 K = 24.12 L

so, moles of H2 = volume of water displaced / 24.12 L

or Pressure of Hydrogen can be used to calculate moles of H2 : PV = nRT .

From moles of H2 evolved you can calculate % Al by using graph.  

  

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