Question

Class Worksheet Chapter 98p16 (2) (Protected View) - Word out References Mailings Review View Help Tell me what you want to do Enable Editing the Internet can contain viruses. Unless you need to edit it's safer to stay in Protected View 2) How many moles of oxygen are required to burn 3.25 moles of butane (C4H10). 2 C4H10 + 13 02 → 8 CO2 + 10 H30 3) Given the following balanced reaction: 2 HCl + Ca(OH)2 → 2H20 +CaCl If5.23 moles of HCl are consumed, calculate: a) The number of moles of calcium hydroxide consumed. b) The number of moles of water formed. c) The number of moles of calcium chloride formed. 4) You want to make 2.3 g of sodium chloride in the following reaction, how many grams sodium bicarbonate do you need? NaHCO3 + HCl → NaCl + H2O + CO2

all of our classes are online now and i have no idea HOW to do this. please explain with steps if you can. thank you!

Answer 1

00 = 3 *3.25 2 2CH. + 139 - 8cg + 104O. According to this equation 13 moles o share required to burn 2 moles butane. . Moles of o required to burn 3.25 moles Cho = (13 moles) *3.25 moles) ICH 2 (2 moles) Mol 2 13 3.25 ? (56) = 21•125 moles: xx2=1343.25 = 21. 1 moles: 3 2HCl + Ca(OH) 240 & cach, amol emol. For 2 moles Hel, imol Carol) is consumed a) For 5.23 moles of Hel, Ca(OH) consumed - li mol) x(5.23 mol) - 2.62 mol. (2mol) b) 2 mol Hll produce 2 mol Ho. 5.23 mol HCl produce 5.23 mol Ho c) amol Hel produce imot cach 5.23 mol HCl produce (1 *5-23)mol cach = 2.62 mol caca 4 xahco + Hol Nacl + H2O + co According to this equation 1 mol Naltco is required to make Imo nach. But here, mass of Nad is given (2.3g). Frasa convert it into moles - 2.39 = 0.03936 mol. 58.449|nd Molar massy Sum of Atomic masses) 22.999 +35.953) Moles = Mass


2.39 moles of Naltco required = moles of Nacl = 0.03936 mol: Mass of Nalco = Moles x Molar mass = 0.03936 mol) (84.007 g/mol) = 3.31 g. Alternatively, imol Nahcą imol Nach : Mass of imol of a ie 84.007 g 58.44 g. compound = Molarmass • ? (OC) uc = 2.3% 84.007 = 3.319. 58.44 5) You have to make a balanced equation first 2H₂ + 2Ho. imol O makes 2 moles HO - 2.999 = 0.09344 mol- Moles of ? = Mass/ Molar mass = 31.9993|mo5 moles of Ho formed - 2x0.09 344 mol = 0.18688 molo Mass of ķ0 = Moles x molar mass =(0.18688 mol) x (18.015 g/mol) = 3.37g. Balanced equatien: PbO + 2HCl → Abcd + yo. Imol - → Imol Moles of Pbo = 0.79g = 0.003539 mol - mol of Pbch. (223.2 9/mol) Mass of Pb c = (0.003539 mol) 278.19/mol) = 0.984 9. bercible to answer

00 = 3 *3.25 2 2CH. + 139 - 8cg + 104O. According to this equation 13 moles o share required to burn 2 moles butane. . Moles of o required to burn 3.25 moles Cho = (13 moles) *3.25 moles) ICH 2 (2 moles) Mol 2 13 3.25 ? (56) = 21•125 moles: xx2=1343.25 = 21. 1 moles: 3 2HCl + Ca(OH) 240 & cach, amol emol. For 2 moles Hel, imol Carol) is consumed a) For 5.23 moles of Hel, Ca(OH) consumed - li mol) x(5.23 mol) - 2.62 mol. (2mol) b) 2 mol Hll produce 2 mol Ho. 5.23 mol HCl produce 5.23 mol Ho c) amol Hel produce imot cach 5.23 mol HCl produce (1 *5-23)mol cach = 2.62 mol caca 4 xahco + Hol Nacl + H2O + co According to this equation 1 mol Naltco is required to make Imo nach. But here, mass of Nad is given (2.3g). Frasa convert it into moles - 2.39 = 0.03936 mol. 58.449|nd Molar massy Sum of Atomic masses) 22.999 +35.953) Moles = Mass