Question

What are the energies expressed in keV of the Ka1 and La1 fluorescence photons for lead (Pb), tungsten (W), molybdenum (Mo), cadmium (Cd), and telluride (T)?

Answer 1

For fluorescence photons energies we can use the Mosley's empirical formula:

Where h is the Planck's constant (6.626 x 10^-34Js)

Z is the atomic number of the element

Now Z for the given elements:

Pb (Z=82)

W (Z=74)

Mo (Z=42)

Cd (Z=48)

Te(Z=52) (Tellurium not telluride)

Using these values we can calculate the Energies of the required fluorescence photons:

For Pb:

For W:

For Mo:

For Cd:

For Te:

These are the required energies in KeV for the given elements

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