Homework Answers
x̅ = 8.16, s = 1.48, n = 55
95% Confidence interval :
At α = 0.05 two tailed critical value, z_c = ABS(NORM.S.INV(0.05/2)) = 1.960
Lower Bound = x̅ - z_c*s/√n = 8.16 - 1.96 * 1.48/√55 = 7.769
Upper Bound = x̅ + z_c*s/√n = 8.16 + 1.96 * 1.48/√55 = 8.551
(7.769, 8.551)
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